LYDSY 1968
题目大意
暂无
题目解法
暂无
RTFC
#include <cstdio>
int m, n;
int main()
{
scanf("%d", &n);
for (int i = 1; i <= n; i++) m += n / i;
printf("%d", m);
return 0;
}
暂无
暂无
#include <cstdio>
int m, n;
int main()
{
scanf("%d", &n);
for (int i = 1; i <= n; i++) m += n / i;
printf("%d", m);
return 0;
}