LYDSY 1028
题目大意
暂无
题目解法
暂无
RTFC
#include <cctype>
#include <cstdio>
inline void readInt(int &x)
{
int ch = x = 0;
while (!isdigit(ch = getchar()))
;
for (; isdigit(ch); ch = getchar()) x = x * 10 + ch - '0';
}
int n, m, a[410], b[410], ans[410], sum;
bool check()
{
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= n; j++) b[j] = a[j];
int Ans = 0;
if (b[i] >= 2)
{
b[i] -= 2;
Ans += 2;
for (int j = 1; j <= n; j++)
{
Ans += 3 * (b[j] / 3);
b[j] %= 3;
if (b[j] == 0 || b[j + 1] == 0 || b[j + 2] == 0) continue;
b[j]--, b[j + 1]--, b[j + 2]--;
j--;
Ans += 3;
}
}
if (Ans == m * 3 + 2) return true;
}
return false;
}
int main()
{
readInt(n), readInt(m);
for (int i = 0, x; i <= m * 3; i++)
readInt(x), a[x]++;
for (int i = 1; i <= n; i++)
{
a[i]++;
if (check()) ans[sum++] = i;
a[i]--;
}
if (sum == 0)
puts("NO");
else
for (int i = 0; i < sum; i++)
printf(i != sum - 1 ? "%d " : "%d", ans[i]);
return 0;
}