CODEFORCES ROUND #368 (DIV. 2) C
题目大意
暂无
题目解法
暂无
RTFC
#include <cstdio>
int main()
{
long long n;
scanf("%I64d", &n);
n == 1 || n == 2 ? printf("-1") : n & 1 ? printf("%I64d %I64d", (n * n - 1) / 2, (n * n + 1) / 2) : printf("%I64d %I64d", (n / 2) * (n / 2) + 1, (n / 2) * (n / 2) - 1);
return 0;
}