CODEFORCES ROUND #366 (DIV. 2) B
题目大意
暂无
题目解法
暂无
RTFC
#include <cstdio>
int n, tmp, times;
int main()
{
scanf("%d", &n);
for (int i = 0; i < n; i++)
{
scanf("%d", &tmp);
if (tmp > 1) times += tmp - 1;
printf("%d\n", ((times &= 1) ^ 1) + 1);
}
return 0;
}